0=-3x-4.9x^2+500

Solution for 0=-3x-4.9x^2+500 equation:

0=-3x-4.9x^2+500

We move all terms to the left:

0-(-3x-4.9x^2+500)=0

We add all the numbers together, and all the variables

-(-3x-4.9x^2+500)=0

We get rid of parentheses

4.9x^2+3x-500=0

a = 4.9; b = 3; c = -500;
Δ = b2-4ac
Δ = 32-4·4.9·(-500)
Δ = 9809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{9809}}{2*4.9}=\frac{-3-\sqrt{9809}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{9809}}{2*4.9}=\frac{-3+\sqrt{9809}}{9.8}
$